LSAT 81, Logic Game 4, Question 20, LSATHacks

Before doing a general could be true, it’s good to skim all the answers and see which are plausible and which aren’t. I find narrowing it down to a couple of candidates in order to brute force only those helps clear the mind.

D and E are clearly wrong. F and H can’t go together, and every product manager must go at least once. So, neither F nor H can go everywhere (because then the other would have nowhere to go)

If you got question 19 right, you’ll recognize C is wrong. Ibanez goes exactly twice (rule 1), and as we saw in the setup, they must go in Sydney (because G can’t go there, so I + F/H must). Therefore Ibanez can’t also go in Manila and Tokyo: that would be three cities.

That leaves A and B. Now that there are only two contenders, we can try drawing both.

A places F and I in Manila:

We know that G must go in Tokyo, since it can’t go in Sydney. Then we can put either F or H in the other spots. Here’s one example:

So, this works. A is CORRECT.

Let’s try B, just to be sure. It places G and I in Tokyo:

Manila is the big space left to fill. We have already placed both I’s, so the only managers who can go in Manila are G + F/H. And here’s the problem: if we place G in Manila, then we’d have to put H in Tokyo (rule 3). But, Tokyo is full. So, B doesn’t work.

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