This is a general could be true question. It’s easiest to use process of elimination. Here are the two scenarios from the setup:
- A is wrong because there’s only one G, and it has to have Q before it. If G is on Monday, there’s no space to put Q before it.
- B is wrong because in both scenarios Tuesday is full: either Q or G must go there. So N can’t go Tuesday.
- C is wrong because rule 2 says two specials can’t go in a row. P is already on Thursday, so it can’t go on Wednesday too.
- D is wrong because G needs Q before it (rule 4). Pizza is the special the day before Friday, so G can’t go on Friday.
That leaves E. This diagram proves it is possible. So, E is CORRECT.
To make a diagram like this, start by putting Q Saturday. Then see who is left to place (QG, L, N), and put them into valid positions. I started with QG first. Once that was set, I knew there were no ordering restrictions on L or N, so they could go anywhere.
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