LSAT 82, Logic Game 4, Question 23, LSATHacks

This question places W on J and S, but not M. So, we get the following diagram:

R can’t be in M or S. Why? Because anything in M is also in S (rule 3), and R and W can’t be in S together (rule 2).

This means R must go in J, as it’s the only space open to them. We have to place G, and we have to fill M. So G will have to go in M, since they’re the only one left:

This is a could be true question. B is CORRECT. G could go in jitsuaku of course, but he doesn’t have to, so this answer works.

All of the other answers contradict the diagram. A and C say that G isn’t presenting on M, but we need someone to present there. G is the only one who can.

D directly violates rule 3! If R is on M, they must be on S (rule 3). This forces R and W together, violating rule 2. Answers are rarely this flagrantly wrong.

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