LG Game 3 Question 15 Explanation, by LSATHacks
To solve a “is completely determined” question, you should ask yourself who is particularly restrictive and important. I would say F and H are both important. If one is out, then the other must be in, and be treasurer.
Of the two, F is more restrictive to have in. If F it in, then G is out. So, putting H out would be a fairly restrictive scenario. Let’s draw that.
H is out, so F is in, so G is out. There are only six people, so if two are out, then all the others have to be in. That’s K, J and L.
K can’t be in T or C, so they must go in M. That leaves J and L to go in C:
Everything is determined, so C is CORRECT.
A is wrong because it’s less restrictive than C: since F is out, F could be in. And K, L and J are all easy to place out: there are no rules forcing them to do anything (as long as H isn’t a councillor).
The key to solving these questions is to look for a chain reaction. H causes that chain reaction by forcing F in, and G out. J, K and L force nothing at all.
Leave a Reply