LSAT 88, Logic Game 3, Question 14, LSATHacks

LG Game 3 Question 14 Explanation, by LSATHacks

We’re looking for two people who can have identical arrangements. Therefore, Zepi is out, as no one else can have the one H one R combo. Looking at our diagram, we can see that no one can have Solomon’s RR combo, so he’s out too. Now we can eliminate any answer choice that mentions Solomon or Zepi. Ursula and Will can’t have the same arrangement since Ursula does’t have space for Will’s GG combo. Thus, answer choice C is CORRECT.

A is wrong since Solomon needs two R’s and Tabitha can’t use any R’s. Thus they can’t have identical arrangements.

B is wrong since Ursula can only use one R so she and Solomon can’t have the same arrangement.

D is wrong since Ursula can’t have two G’s so she and Will (two G’s) can’t have the same arrangement.

E is wrong since Zepi is the only one who can have one R and one H so no one can have the same arrangement him.