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LSAT Explanations › Preptest 88 › LSAT Preptest 88 Logic Games Explanations › Question 17

LSAT 88, Logic Game 3, Question 17, LSATHacks

LSAT 88 Explanations

LG Game 3 Question 17 Explanation, by LSATHacks

We’re changing the game’s rules here. Now we’re told Zepi and at least one other person uses exactly one H and one R. Who could this person be?

It can’t be S, since S still has two Rs.

It could be T, since the rule now allows T to have Rs.

It could also be U. Under this new rule, U could have 2 Gs or 2 Ls.

It could also be W. We’d just add one R and one H.

What is the overall effect? If the other person also has the HR combo, then to get overall 3 types of flowers, they must use two Gs since only one person in the game can use two Ls. So what must be true is that at least one person doesn’t use any Ls! Therefore E is CORRECT.

LSAT Preptest 88, Game 3, Question 17, Diagram 7

A is incorrect since Tabitha would need two Rs under the new rules.

B is incorrect. Looking at our new diagram, we can see that everyone uses at least one R.

C is incorrect. In this new diagram, Zepi, Will, and Ursula can all have one rose and one hyacinth.

D is incorrect. While Solomon could use no hyacinths, but he doesn’t have to.

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Comments

  1. Patrick A says

    September 3, 2023 at 7:43 pm

    Why does Tabitha needs two Rs? Why not an R and a G? Plus, I thought only Solomon could have 2 Rs.

    Reply

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