LSAT 88, Logic Game 4, Question 23, LSATHacks

H and K can only go together on Friday. If they were together on Wednesday, then J would be on Thursday, and G would be on Friday. This is too many clients between K and G.

If they were together on Thursday, we can’t have out JG block.

Okay, so H and K are on Friday, and H is in the morning due to Rule 1. Then, to make sure there’s at most one client before G and K, G will have to go on Thursday afternoon.

We know J has to go on the day before G. Now we can have two configurations. In the first one, J goes on Wednesday morning, so L has to go on Thursday morning.

In the second configuration, J goes on Wednesday afternoon, and L can go on either Wednesday or Thursday morning.

Thus, C is CORRECT. J can go on either Wednesday morning or afternoon.

A is incorrect. G can’t be on Friday since H and K fill all the slots.

B is incorrect since H must go on Friday.

D is incorrect. K must be on Friday.

E is incorrect. L can’t be scheduled on Friday since H and K are there.

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