LSAT 34, Logic Game 4, Question 21, LSATHacks

LG Game 4 Question 21 Explanation, by LSATHacks

We need to find the lowest number at Souderton. Let’s start with the diagram above. We definitely need one of O or J at S. 

This eliminate A. We can’t have zero people at S.

Let’s try the diagrams. If we put P in R, then K, O and N are at S. Three people are at S. So E is wrong.

Let’s see if we can do better, and try Nr instead. That only causes 2 people to be in S.

We can’t get that number any lower. J has to be at S, because one of O/J has to be there. And if we moved P into R, we’d be in the scenario from the first diagram.

C is CORRECT. Two is the lowest number of doctors we can have at S.

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