Having an I in each group restricts things quite heavily.
First, there are no H in this scenario. H’s and I’s can’t go together (rule 4). This eliminates B.
Second, there can be at most 2R in any group in this scenario. I’s and 3R can’t go together (rule 4). This eliminates E.
Third, this means that the only possible variables left to place are 3R, split between groups two and three. There are a total of six variables in this question, at most.
(Note that we don’t need to place any R: it’s possible to place no variables in this game.)
Here’s our base scenario:
A is CORRECT. Here’s how it looks:
C is wrong because R can’t go in group one. So there’s no way to put anything there apart from the single I we already have.
D is wrong because there are only 3R left to place in those two groups. We have a max of five variables to put in groups 2 and 3.
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