Having an I in each group restricts things quite heavily.

First, there are no H in this scenario. H’s and I’s can’t go together (rule 4). This eliminates **B.**

Second, there can be at most 2R in any group in this scenario. I’s and 3R can’t go together (rule 4). This eliminates **E.**

Third, this means that the only possible variables left to place are 3R, split between groups two and three. There are a total of six variables in this question, at most.

(Note that we don’t need to place any R: it’s possible to place no variables in this game.)

Here’s our base scenario:

**A **is **CORRECT. **Here’s how it looks:

**C **is wrong because R can’t go in group one. So there’s no way to put anything there apart from the single I we already have.

**D **is wrong because there are only 3R left to place in those two groups. We have a max of five variables to put in groups 2 and 3.

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Thu says

Hi,

I was just wondering why there would have to be “3R’s” in this answer.. I understand max of three but couldn’t there be 2R or even 1R

I think I am missing something.

Thanks for your help!

FounderGraeme Blake says

Thanks. I meant we could place 3R at most. I added this line for clarity. We could even place zero R:

(Note that we don’t need to place any R: it’s possible to place no variables in this game.)

N says

Hi,

I’m really not clear on why we only have 3R to split. If I understand correctly, groups 2 and 3 can have at most 2R each, so doesn’t that leave us with 4R to split between the two?

Neh says

Hi,

Could you please explain the reasoning behind this statement:

“Third, this means that the only possible variables left to place are 3R, split between groups two and three. There are a total of six variables in this question, at most.”

Why can’t there be 4R?