This is an explanation of the second logic game from Section IV of LSAT Preptest 75, the June 2015 LSAT.
Seven trees will be planted on three lots (1, 2, 3). The trees are: a hickory, a larch, a maple, an oak, a plum, a sycamore, and a walnut (H, L, M, O, P, S, W). You must determine which trees can be planted on which lot according to the rules.
This is a grouping game. We have to place seven trees in three lots.
From experience with similar games, it’s best to set this game up vertically:
Next, read over all the rules. You shouldn’t just blindly draw the rules in order. Some rules are easier to draw than others, because they can go directly on the diagram. Draw these first.
Rules 3, 4 and 5 can go directly on the diagram:
A couple notes on the symbols:
Technically, L/W and M/O are exclusive. You can’t have both. I know I’ll remember that because I’ve seen similar rules. If you aren’t certain you’ll remember, it’s best to make a separate note. Maybe “
L/W” to the left of lot one, for example.
Lot three has at least two trees, because it has more than lot 1. The arrow + greater than sign is a second reminder of this rule.
This final rule is incredibly important. In every scenario you make you must check if lot three has more than lot one. And in some cases, the final rule determines the distribution.
For example, some questions place exactly three trees in lot two. This means that lot 1 has one tree and lot 3 has three trees – that’s the only way to divide the trees between those two lots and still obey the final rule.
The other two rules can’t be drawn directly, so you should put them in a numbered list:
The circled P and S means that those two variables have no rules. The “H O __” means that the hickory and the oak are in a lot together with one other tree.
I couldn’t make any deductions that I could draw. However, it’s important to consider numerical distributions.
We have seven trees. At least one is in lot 2. That leaves six trees to divide between lot 1 and 3. And lot 3 needs more than lot 1.
That means we can’t put three trees in lot 1, because then there would only be three trees to put in lot 3.
So lot one has, at most, two trees. I didn’t write this down because it’s fairly straightforward if you remember the final rule. But it you sometimes make mistakes with numerical distributions, you should write this deduction down.
Likewise, it’s important to consider where you could place the hickory, oak and 3rd tree (rule one). They could only go in lots 2 or 3, because lot 1 can’t have three trees.
Need help with LG? → Try the LG Mastery Seminar
Solve hard games quickly