LSAT 77, Logic Game 3, Question 16, LSATHacks

LG Game 3 Question 16 Explanation, by LSATHacks

This question says that Paulson selects W. That’s Paulson’s final choice, so they must have chosen last.

Answers A-C are hard to think about because they’re less concrete. It’s best to skip them to think about the concrete answers.

D isn’t possible. If Jackson selects X, they don’t go first. So only L and T are left to go first, and both of them would select X – meaning Jackson couldn’t select X.

E is CORRECT. This diagram shows how the order could work.

(Note that I did this in my head in timed conditions – I’m only showing this drawing in order to make the explanation clear.)

Now, I’ll explain why A-C are impossible. But on timed conditions, it’s probably better just to skip them.

A: We’re only looking at J, L and T, since the question says Paulson selects W. Look at each of J, L and T in turn, and you’ll see it’s impossible for two people to get their second choice:

• J first, picks Y. Only L can get their second choice.
• L first, picks X. Only T can get their second choice.
• T first, picks X. Only L can pick their second choice.

B is impossible. If you look at the third choices of J, L and T, they’re Z, W and Z. W can’t be chosen, because P has W. So only Z is left, and only one person can take Z.

C is impossible. Only X and Y are possible first choices, so it’s not possible for three people to have their first choice.