This question places R alone. That means the group structure will be 1-2-3. R alone, two others in markets, and three in a third group. Like this:

I’m purposefully leaving off the group labels, because I want you to think about how to separate the assistants into the three groups. For example, Y/V are split between the two other groups, because rule 3 says they can’t be together.

Next, TS is hardest to place. Needs two spaces. So, TS must go in the group of three:

That leaves only Z left to place, and only one spot open:

So we have figured out the entire distribution of assistants between the 1-2-3 groups!* *And guess what, that solves the question. We know that the group of two is Markets (rule 1). So, we know for sure that Z is in markets. **D **is **CORRECT. **

You could also have gotten the right answer by making diagrams figuring out which of the groups above go in L, M and P. But it would have taken *longer. *And on logic games you should always learn the fastest method.

(Adding in the three groups would have complicated things by forcing you to think about whether YZ were in P together, for example.)

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Alex says

Please help me.

Why can’t E be correct… Why isn’t it necessary that S + T go in Pricing. If they go in M they force Y and Z into pricing and violate the rule that says Y can’t go with V.

Please help. I feel like my logic circuit is breaking and I don’t know what to do.

TutorRosalie (LSATHacks) says

There are two possible setups for this question. They look like this:

Diagram 1

L M P

R Y S

Z T

V

Diagram 2

L M P

S Y/V R

T Z

Y/V

While in Diagram 1, ST have to go in Pricing, because otherwise Y and V would be forced together. But that isn’t true for Diagram 2. In Diagram 2, R occupies Pricing and is the only assistant assigned (as per the question’s instuctions). Because Rule 3 says that Y and V can’t be assigneed together, we know that one of them will go in L and one will go in M. ST must go together so they must both be assigned to L in this case. Thus, in both diagrams, Z being assigned to M is the only constant, making D the correct answer.