LSAT 82, Logic Game 3, Question 15, LSATHacks

This question is a general could be true. There’s no upfront work, so you should refer to the three setup scenarios and look to see if the answers could be true in any of them.

Note, it’s helpful to be able to visually move the variables down onto the diagram correctly in your minds eye. When the variables are drawn so close to the diagram, this is a learnable skill. It saves a lot of drawing. For example, when looking at scenario 1, I can visualize G in 2nd and Ikaba in 4th, or vice versa. So you can imagine either variation without drawing them fully.

A and B are wrong because Q can only go once. That’s because the same investigator must interview G and H. Q can’t, because Q is already interviewing F. An interviewer can interview at most two people.

C doesn’t work in any scenario. Rule 4 says R must conduct the third interview. And no investigator can conduct three interviews. So R can’t do the 2nd, 3rd and 4th interviews!

D is CORRECT. In scenario 3, S could do the first and second interviews if Ikaba is third. Shaw would interview G and H, fulfilling rule 1.

E is wrong because it contradicts the scenarios above. In scenarios 2 and 3, Q is 2nd and 4th, respectively. And in scenario 1, Shaw only interviews Ikaba. It is Rivera who conducts two interviews (since Rivera interviews H, they must also interview G. See rule 1.)

Quick Jump PT Section Que