LSAT 90, Logic Game 3, Question 15, LSATHacks

We’re looking for a combination that can’t go together in either semester. There are actually only three ways for an answer to be illegal:

• To have H without M in Fall
• To have V without T in Spring.
• To have a season without V or M

If you quickly skim the answers, you’ll see that each has V or M, so no answer can be proven based on that. We’ll have to use the first two rules.

To evaluate answers, think about what would be hardest. It would be an answer with neither H nor V (leaving them both in the other group) or an answer with both H and V, making at least one rule apply no matter which group they’re in.

C is CORRECT. It has both H and V. Let’s consider what happens if we have H, O and V together:

• If we put them in Fall, there is no space for M (rule 1)
• If we put them in Spring, there is no space for T (rule 2)

So either way we violate a rule.

For the incorrect answers, you can refer to diagrams and reasoning in the previous questions to eliminate A, B and D. If you have your diagrams clearly arranged on scrap paper it should be very quick to scan over them and find scenarios that prove wrong answers are possible.

A can be eliminated since H, M, and T can show up together in this diagram from Question 12:

H, M, and V also host together in this partial diagram from Question 14, so we can eliminate B:

F: H, V, M

S: V, T

The same is true of D. In the diagram above, the final spot in spring is open. There are no remaining rules, so we can place H there, and we’d have Honolulu, Tampa and Vancouver together legally.

As for E you can show it is possible with this scenario:

F: M, O, V

S: H, T, M

This obeys all three rules.

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