LG Game 2 Question 9 Explanation
This is a counting question. Look at both diagrams, and see how many birds can be in.
If W is in, then W, G, and S are in. That’s 3 birds.
On this diagram, S, J, M and H are can be in. That’s 4. C is CORRECT.
Yes, you read that right. S can be in. Here’s how.
Start with J in. Don’t start with S out – you’re trying to put birds in!
If J is in, H is in. You can also put M in. J, M and H make three.
Only S is left. You don’t know anything about S if you start with J. Remember, you can only read the diagram left to right.
You can also put S in. Both S and J can be in together. S, J, M and H make four.
Review the setup if you’re not sure why S and J can both be in.
Want a free Logic Games lesson?
Get a free sample of the Logic Games Mastery Seminar. Learn tips for going faster at logic games
Hi, I'm Graeme Blake
I run LSAT Hacks, and got a 177 on the LSAT. The single best thing I've ever made is the set of LSAT Mastery seminars. They show you how to think like a 170+ scorer when doing questions. Get them here: Mastery Seminars
I guarantee you'll like them, or you get your money back within 7 days. There's no risk. Check the reviews, people have said they improved within a few days.
---------
Photos and Updates: You can follow me on Instagram here
For updates, sign up for my email list. I update whenever I have new posts.
Why can’t all six be in? If S were in, that would fail the sufficient and make everything downstream technically irrelevant. It wouldn’t be triggered. I know that I am wrong; however, I would like to understand when a sufficient or necessary failing means that other relationships do not matter versus when other relationships continue to apply. Thank you so much.
You can refer back to the setup page for a more comprehensive explanation. If S were in, it would not make everything downstream irrelevant because of the way it is related to J. The relationship says that if J isn’t in, then S is. This means that S is required for J to not be in. So it isnt’ the case that they can’t be in together, but that for J to be allowed to be out, S has to be there.
So we can have 3 cases: J and S both in, J in and S out, and S in and J out. So in this case, S doesn’t trigger anything, but elements down the rest of the chain would trigger for some to be out. For example, if J is in, then Rule 2 states that H must be in. Rule 1 and Rule 3 together then say that G and and W would then be out.