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LSAT Explanations » LSAT Preptest 33 » Logic Games » Question 9

LSAT 33, Logic Game 2, Question 9

LSAT 33 Explanations

LG Game 2 Question 9 Explanation

This is a counting question. Look at both diagrams, and see how many birds can be in.

LSAT PrepTest 33, Game 2, Question 9, Diagram 1

If W is in, then W, G, and S are in. That’s 3 birds.

LSAT PrepTest 33, Game 2, Question 9, Diagram 2

On this diagram, S, J, M and H are can be in. That’s 4. C is CORRECT.

Yes, you read that right. S can be in. Here’s how.

Start with J in. Don’t start with S out – you’re trying to put birds in!

If J is in, H is in. You can also put M in. J, M and H make three.

Only S is left. You don’t know anything about S if you start with J. Remember, you can only read the diagram left to right.

You can also put S in. Both S and J can be in together. S, J, M and H make four.

Review the setup if you’re not sure why S and J can both be in.

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Comments

  1. Ravi Sandhu says

    October 1, 2020 at 5:18 am

    Why can’t all six be in? If S were in, that would fail the sufficient and make everything downstream technically irrelevant. It wouldn’t be triggered. I know that I am wrong; however, I would like to understand when a sufficient or necessary failing means that other relationships do not matter versus when other relationships continue to apply. Thank you so much.

    Reply
    • TutorRosalie (LSATHacks) says

      October 9, 2020 at 9:11 pm

      You can refer back to the setup page for a more comprehensive explanation. If S were in, it would not make everything downstream irrelevant because of the way it is related to J. The relationship says that if J isn’t in, then S is. This means that S is required for J to not be in. So it isnt’ the case that they can’t be in together, but that for J to be allowed to be out, S has to be there.

      So we can have 3 cases: J and S both in, J in and S out, and S in and J out. So in this case, S doesn’t trigger anything, but elements down the rest of the chain would trigger for some to be out. For example, if J is in, then Rule 2 states that H must be in. Rule 1 and Rule 3 together then say that G and and W would then be out.

      Reply

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