LSAT 90, Logic Game 1, Question 4, LSATHacks

This question tells us that Roth’s call was local, which automatically rules out it being third (due to Rule 4).

That means we are in scenario 2 or 3:

Scenario 2:

Scenario 3:

Since this is a must be false question, before making any further drawings you should simply check if one of the answers contradicts both scenarios. S, Q and V are likely candidates, as they have set positions in each diagram. You can eliminate answers if the answer is possible in either scenario.

Scenario 2 eliminates A: Q can be fourth

B and D are not good candidates, as both R and T are flexible: between the two scenarios they can each go anywhere except third.

C is CORRECT. S can’t be second in either diagram.

The second scenario eliminates E: V is fifth in that scenario.

Note that you also could have eliminated the answers using a prior question and using impossibility.

Question 2 eliminates B and D. The scenario there placed R second and T first.

It is impossible for A or E to be correct. This is because if Q is fourth (A) then V is fifth (E), and vice versa. The answers are either both true or both false, and we can’t have two correct answers, so you can eliminate both.

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