LSAT 90, Logic Game 1, Question 5, LSATHacks

This question tells us the first call was nonlocal. If the first is nonlocal and the third is also nonlocal, then this heavily restricts T and Q: both need to be local, so neither T nor Q can be first or third.

QV are the most restricted, since we need two slots for them and now Q can’t be local. So let’s think about where to put them. We can’t put them second:

The problem is that S goes first to be in front of Q (rule 1), but rule 2 says that S and V need to have different call types. However, for this question calls 1 and 3 are both nonlocal. Meaning S and Q would be the same call type.

So, we instead need to put QV fourth and fifth:

The next most restricted variable is T. It has to be a local call, so it can only go second, because 1st and 3rd are both nonlocal:

S and R are the two others left to place. They can go in either slot. The only restriction on S is it needs to have a different type of call than V. Since only 1st and 3rd are open to S and both those calls are nonlocal, this forces V to be local.

This question is about how many call’s positions are fixed. There are three calls fixed, T, Q and V. So C is CORRECT.

This analysis eliminates all other answer choices. T, Q and V are fixed, so A and B are wrong: three need to be fixed, not 1 or 2. R and S aren’t fixed, so more than three calls being fixed isn’t correct either.

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