LSAT 90, Logic Game 2, Question 8, LSATHacks

If Jasmine plays in the second game, then G can’t go second (rule 4). And G can’t go first either (rule 1). So, this means G must be third:

The next most restricted person is F: they must play against G or H, needing two spaces. They can’t be in group 1 (rule 1), and group 2 only has 1 space (because J is there) so F + G/H can only go in group 3. F thus plays with G and therefore F cannot go with H:

H, L and M are left to place, and they can each go anywhere. At this point we can check our answers. A–D are all wrong, as they involve F and G not playing against each other. Yet we know they must.

E is CORRECT. We can play H and L in group 1, and then M in group 2 with J:

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