LSAT 90, Logic Game 2, Question 9, LSATHacks

F can play against H in either Game 2 or Game 3. Let’s draw both scenarios and see what we can deduct: one with FH second, one with FH third.

G can only go in groups 2 or 3 (rule 1). Since FH fill one of those groups in each scenario, that forces G to go 3rd in scenario 1, and 2nd in scenario 2:

J can’t go with G (rule 4), so this in turn forces us to place J in group 1. In scenario 1 we also must place L, since it can’t go in group 3 (rule 2):

Only M is left to place in scenario 1, and only M, L in scenario 2. The question is asking for something that must be true, and since J is in group 1 in both groups, that is the only possible answer. C is CORRECT.

(I didn’t draw in M and L because there’s no point to completing diagrams once you already answer a question. When you get far enough through the logical steps and hit “could be true” situations, you should check the answers to see if you already solved the question.)

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